Advertisements
Advertisements
प्रश्न
A solid weighs 120 gf in air and and 105 gf when it is completely immersed in water. Calculate the relative density of solid.
उत्तर
Weight of solid in air , W1 = 120 gf
Weight of solid when completely immersed in water W2 = 105 gf
R.D. of solid = `W_1/(W_1 - W_2) xx "R.D. of water"`
R.D. of solid = `120/(120 - 105) xx 1`
R.D. of solid = 8
APPEARS IN
संबंधित प्रश्न
Complete the following sentence.
S.I. unit of density is .......... .
Complete the following sentence.
Density in kg m-3 = ............ × density in g cm-3
Relative density of a substance is expressed by comparing the density of that substance with the density of :
The unit of relative density is :
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
An iceberg floats in sea water of density 1.17 g cm 3, such that 2/9 of its volume is above sea water. Find the density of iceberg.
