Question

A steel wire of length 1 has a magnetic moment m it is then bent into a semicircular arc. The new magnetic moment is

विकल्प

• m

• 2m/π

• m/π

• m × s

Answer 1

2m/π

Explanation:

m = m × 1 Where each pole's strength is insufficient.

When 1 = ${\displaystyle \pi r+r=\frac{1}{\pi }}$

Distance between poles = ${\displaystyle 2r=\frac{2l}{\pi }}$

M¹ = ${\displaystyle m\times \frac{21}{\pi }=\frac{2m}{\pi }}$