Advertisements
Advertisements
प्रश्न
A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 6 N. Draw a diagram to show the application of forces and calculate the moment of forces applied.
उत्तर
Diameter of steering wheel = 0.5 m
Radius = `"d"/2`
= `0.5/2`
= 0.25 m
Magnitude of force = 6 N
Moment of couple = 6N × 0.5 m
= 3 N m
APPEARS IN
संबंधित प्रश्न
How does the magnitude of this non-contact force on the two bodies depend on the distance of separation between them?
Name the factors affecting the turning effect of a body
Moment of force = force × perpendicular distance of force – from the pivoted point.
State the S.I. unit of moment of force.
On what factors does the effect of thrust on a surface depend?
A rocket is moving at a constant speed in space by burning its fuel and ejecting out the burnt gases through a nozzle. Answer the following
1) Is there any change in the momentum of the rocket? if yes, what causes the change in momentum?
2) Is there any force acting on the rocket? if yes, how much?
What do you understand by the clockwise and anticlockwise moment of force? When is it taken positive?
Classify the following amongst contact and non-contact forces.
electrostatic force
Write the expression for calculating the moment of force about a given point.
A metal rod AB of length 80 cm is balanced at 45 cm from the end A with 100 gf weights suspended from the two ends.
- If this rod is cut at the centre C, then compare the weight of AC to the weight of BC.
- Give a reason for your answer in (a).
