हिंदी

A string of length 0.5 m carries a bob of mass 0.1 kg at its end. If this is to be used as a conical pendulum of period 0.4 π sec, the angle of inclination of the string with the vertica -

Advertisements
Advertisements

प्रश्न

A string of length 0.5 m carries a bob of mass 0.1 kg at its end. If this is to be used as a conical pendulum of period 0.4 π sec, the angle of inclination of the string with the vertical is ______. (g = 10m/s2)

विकल्प

  • 0.4

  • 0.6

  • 0.7

  • 0.8

MCQ
रिक्त स्थान भरें

उत्तर

A string of length 0.5 m carries a bob of mass 0.1 kg at its end. If this is to be used as a conical pendulum of period 0.4 π sec, the angle of inclination of the string with the vertical is 0.8. (g = 10m/s2)

Explanation:

`T=2pisqrt((Lcostheta)/g)`

`costheta=(gT^2)/(4pi^2L)=(10(0.4pi)^2)/(4pi^2xx0.5)=(10xx0.16pi^2)/(2pi^2)`

`=10xx0.08=0.8`

shaalaa.com
Applications of Uniform Circular Motion
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×