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प्रश्न
A transverse wave is represented by y = 2sin (ωt - kx) cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be ______.
विकल्प
4π
2π
π
2
MCQ
रिक्त स्थान भरें
उत्तर
A transverse wave is represented by y = 2sin (ωt - kx) cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be 4π.
Explanation:
y = 2sin (ωt - kx)
Maximum particle velocity, vm = Aω
wave velocity, vp = `omega/k`
vp - vm
`omega/k = Aomega`
k = `1/A = (2pi)/lambda`
λ = 2πA = 2π × 2 = 4π
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Wave Motion
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