हिंदी

A transverse wave propagating along the string is y = 0.3 sin (x + 20t) where x, y are in metre and t in second. The linear density of the string is 1.2 x 10-4 kg/m. The tension in the string is -

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प्रश्न

A transverse wave propagating along the string is y = 0.3 sin (x + 20t) where x, y are in metre and t in second. The linear density of the string is 1.2 x 10-4 kg/m. The tension in the string is ______.

विकल्प

  • 0.072 N

  • 0.024 N

  • 0.096 N

  • 0.048 N

MCQ
रिक्त स्थान भरें

उत्तर

A transverse wave propagating along the string is y = 0.3 sin (x + 20t) where x, y are in metre and t in second. The linear density of the string is 1.2 x 10-4 kg/m. The tension in the string is 0.048 N.

Explanation:

y = 0.3 sin (x + 20t)

v = `sqrt("T"/"m")`   ∴ T = v2m

`"dy"/"dt" = 0.3 xx 20 cos (x + 20"t")`

`("dy"/"dt")_"max" = 6`

∴ T = 3.6 × 1.2 × 10-4 kg/m

= 43.2 × 10-4 kg

= 0.00432 = 0.0423 N

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