Advertisements
Advertisements
प्रश्न
A two digit number is such that the product of the digit is 12. When 36 is added to the number, the digits interchange their places. Find the numbers.
उत्तर
Let this two digit number be xy. Which means x=10x (as it comes in tens digit).
Then as per the question,
xy = 12, ....... (i)
10x + y + 36 = 10y + x
⇒ 9x - 9y + 36 = 0
⇒ x - y + 4 = 0 ....... (ii)
Putting x = `12/"y"` from (i) in (ii) , we get,
`12/"y" - "y" + 4 = 0`
⇒ y2 - 4y - 12 = 0
⇒ y2 - 6y + 2y - 12 = 0
⇒ y ( y - 6 ) +2 (y-6) = 0
⇒ (y - 6)(y + 2) = 0
⇒ y = 6, hence from (i), x=2.
Hence the number is 26
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
x2 - x - a(a + 1) = 0
The sum of two numbers is 8 and 15 times the sum of their reciprocals is also 8. Find the numbers.
The hypotenuse of a right triangle is `3sqrt10`. If the smaller leg is tripled and the longer leg doubled, new hypotenuse wll be `9sqrt5`. How long are the legs of the triangle?
Find the tow consecutive positive odd integer whose product s 483.
Solve the following quadratic equations by factorization: \[\sqrt{3} x^2 - 2\sqrt{2}x - 2\sqrt{3} = 0\]
If p and q are the roots of the equation x2 − px + q = 0, then
Solve the following quadratic equation by factorisation:
9x2 - 3x - 2 = 0
Solve the following equation by factorization
`x/(x + 1) + (x + 1)/x = (34)/(15)`
The hypotenuse of a right-angled triangle is 1 m less than twice the shortest side. If the third side is 1 m more than the shortest side, find the sides of the triangle.
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
