Advertisements
Advertisements
प्रश्न
A uniform metre scale is balanced at a 40 cm mark when weights of 20 gf and 5 gf are suspended at 5 cm mark and 75 cm mark respectively. Calculate the weight of metre scale.
उत्तर
A metre scale is a uniform, therefore its weight acts at a 50 cm mark.
Taking moments about to cm mark.
A moment in the clockwise direction,
= W × 10 cm + 5 gf × 35 cm
= 10 W cm + 175 gf cm.
moment in anti-clockwise direction,
= 20 gf × 35 cm
= 700 gf cm.
By the law of moments,
Moments in clockwise direction = moments in anti-clockwise directions.
10 W cm + 175 gf cm = 700 gf cm
∴ 10 W cm = (700 − 175) gf cm
∴ W = `525/10` gf = 52.5 gf.
APPEARS IN
संबंधित प्रश्न
How does the effect of force differ when it is applied on a non-rigid body?
It is easier to open the door by pushing it at its free end.
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2·0 N m. What minimum force must be applied on its rim?
The spanner (or wrench) has a long handle.
State one factor on which the magnitude of a non-contact force depends. How does it depend on the factor stated by you?.
A uniform metre rule of weight 10gf is pivoted at its 0 mark.
What moment of force depresses the rule?
Classify the following amongst contact and non-contact forces.
Frictional force
State one factor on which the magnitude of a non-contact force depends. How does the magnitude of a non-contact force change along with distance?
On a see-saw, two children of masses 30 kg and 50 kg are sitting on one side of it at distance 2 m and 2.5 m respectively, from its middle, where should a man of mass 74 kg sit to balance it?
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is ______.