Question

`abs ((1, "a"^2 + "bc", "a"^3),(1, "b"^2 + "ca", "b"^3),(1, "c"^2 + "ab", "c"^3))`

विकल्प

• -(a - b)(b - c)(c - a)(a² + b² + c²)

• (a - b)(b - c)(c - a)

• (a² + b² + c²)

• (a - b)(b - c)(c - a)(a² + b² + c²)

Answer 1

-(a - b)(b - c)(c - a)(a² + b² + c²)