Question

According to Ampere's circuital law, ______.

विकल्प

• ${\displaystyle \oint \overrightarrow{\text{B}}\cdot \overrightarrow{\text{d}}l}$ = I

• ${\displaystyle \oint \overrightarrow{\text{B}}\cdot \overrightarrow{\text{d}}l={\mu }_0}$I

• ${\displaystyle \oint \overrightarrow{\text{B}}\cdot \overrightarrow{\text{d}}l=\pi {\mu }_0\text{I}}$

• ${\displaystyle \oint \overrightarrow{\text{B}}\cdot \overrightarrow{\text{d}}l=2\pi {\mu }_0\text{I}}$

Answer 1

According to Ampere's circuital law, ${\displaystyle \underline{\oint \overrightarrow{\text{B}}\cdot \overrightarrow{\text{d}}l={\mu }_0\text{I}}}$.

Explanation:

The expression for Ampere’s circuital law is ${\displaystyle \oint \overrightarrow{\text{B}}\cdot \overrightarrow{\text{d}}l={\mu }_0}$I

Where I is the current included in the surface bounded by the line integral.