Question

Acetic acid is 1.1% dissociated in its 0.1 M solution. What is the equilibrium concentration of H⁺ ions in the solution?

विकल्प

• 1.1 × 10⁻¹ mol L⁻¹

• 1.1 × 10⁻³ mol L⁻¹

• 1.1 × 10⁻² mol L⁻¹

• 1.1 × 10⁻⁴ mol L⁻¹

Answer 1

1.1 × 10⁻³ mol L⁻¹

Explanation:

Percent dissociation = α × 100

∴ α = ${\displaystyle \frac{1.1}{100}}$ = 1.1 × 10⁻²

Equilibrium concentration of H⁺ ions

= α × c

= 1.1 × 10⁻² × 0.1

= 1.1 × 10⁻³ mol L⁻¹