Question

Alkene \[\ce{R - CH = CH2}\] reacts with B₂H₆ in the presence of dilute H₂O₂, to give:

विकल्प

• \[\begin{array}{cc}
  \ce{O}\phantom{..}\\
  ||\phantom{..}\\
  \ce{R - C - CH3}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{....}\ce{OH}\phantom{...}\ce{OH}\phantom{}\\
  \phantom{..}|\phantom{......}|\phantom{}\\
  \ce{R - CH - CH2}
  \end{array}\]

• \[\ce{R - CH2 - CHO}\]

• \[\ce{R - CH2 - CH2 - OH}\]

Answer 1

\[\ce{R - CH2 - CH2 - OH}\]

Explanation:

\[\ce{\underset{Alkene}{6H - CH = CH2} + \underset{Diborane}{B2H6} -> \underset{Trialkylborane}{2(R - CH2 - CH2)3B}}\]

\[\ce{\underset{Trialkylborane}{(R - CH2 - CH2)3B} + 3H2O2 ->[OH^-] \underset{Alcohol}{3R - CH2 - CH2OH} + B(OH)3}\]