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प्रश्न
Aluminium carbide reacts with water according to the following equation.
\[\ce{Al4C3 + 12H2O -> 3CH4 + 4Al(OH)3}\]
What volume of methane is obtained from 12 g of aluminium carbide?
उत्तर
\[\ce{Al4C3 + 12H2O -> 4Al(OH)3 + 3CH4}\]
144 g 3 x 22.4 L
67.2 L
144 g of Al4C3 will produce 67.2 L of methane
∴ 12 g of Al4C3 will produce
= `67.2/144 xx 12`
= 5.6 L
संबंधित प्रश्न
Prove the Following :
Oxygen is a diatomic molecule.
Under the same conditions of temperature and pressure you collect 2L of carbon dioxide, 3L of chlorine, 5L of hydrogen, 4L of nitrogen and 1L of sulphur dioxide. In which gas sample will there be :
a. The greatest number of molecules.
b. The least number of molecules.
Justify your answer.
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2CO + O2 → 2CO2
Calculate the volume of oxygen used and carbon dioxide formed in the above reaction.
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\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]
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\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]
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\[\ce{P + 5HNO3 -> H3PO4 + 5NO2 + H2O}\]
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