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प्रश्न
An A.C. circuit consists of inductor of inductance 125 mH connected in parallel with a capacitor of capacity 50 μF. Determine the resonant frequency.
उत्तर
L = 125 mH = 125 × 10−3H,
C = 50 µF = 50 × 10−6F
fr = ?
We have,
= antilog [log (400) – log (6.28)]
= antilog [2.6021 – 0.7980]
= antilog [1.8041]
∴ fr = 63.69 Hz
The resonant frequency in the A.C. circuit is 63.69 Hz.
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