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प्रश्न
An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 r.p.m. The acceleration of a point on the tip of the blade is about:
विकल्प
1600 m/s2
4740 m/s2
2370 m/s2
5055 m/s2
MCQ
उत्तर
4740 m/s2
Explanation:
Since, a = ω2 r
f = 1200 rpm
Now, converting in second
and f = `1200/60`
= 20 `"rad"/"sec."`
Angular velocity of particle
ω = 2πf
= 20 × 2π = 40π
Now acceleration (a) = ω2 r
= (40π)2 × `30/100`
= 4740 m/s2
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Velocity and Acceleration in Simple Harmonic Motion
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