Question

An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10^-29 C.m. What is the potential energy of the electric dipole?

विकल्प

• -20 × 10^-18 J

• -7 × 10^-27 J

• -10 × 10^-29 J

• -9 × 10^-20 J

Answer 1

-7 × 10^-27 J

Explanation:

Potential energy of a dipole is given by

U = -`vec"P".vec"E"` = -PE cos θ

[Where θ = angle between dipole and perpendicular to the field]

= -(10^-29) (10³) cos45°

= -0.707 × 10^-26 J

= -7 × 10^-27J