Question

An electron in an atom is revolving around the nucleus in a circular orbit of radius 0.53 A, with a speed of 2 x 10⁶ m/s. Find the resultant orbital magnetic moment and angular momentum of electron.(e = 1.6 x 10^-19 C, m = 9.1 x 10^-31 kg)

Answer 1

`M_("orb") = (evr)/2`

m_orb = `(1.6 xx 10^-19 xx 2 xx 10^6 xx 0.53 xx 10^-10)/2`

= `1.6 xx 0.53 xx 10^-23`

= `8.48 xx 10^-24` Am²

L = mvr 

L = `9.1 xx 10^-31 xx 2 xx 10^6 xx 0.53 xx 10^-10`

= `18.2xx0.53xx10^-35`

=`9.65xx10^-35J.s`