Question

An electron of stationary hydrogen atom jumps from 4^th energy level to ground level. The velocity that the photon acquired as a result of electron transition will be ______. (h = Planck's constant, R = Rydberg's constant, m = mass of photon)

विकल्प

• `(9"RH")/(16"m")`

• `(11"hR")/(16"m")`

• `(13"hR")/(16"m")`

• `(15"hR")/(16"m")`

Answer 1

An electron of stationary hydrogen atom jumps from 4^th energy level to ground level. The velocity that the photon acquired as a result of electron transition will be `underlinebb((15"hR")/(16"m"))`. (h = Planck's constant, R = Rydberg's constant, m = mass of photon)

Explanation:

`1/lambda="R"(1/eta_1-1/eta_2)`

`1/lambda="R"[1/1-1/16]`

= `(15-"R")/16`

∴ λ = `16/(15"R")`

P = `"h"/lambda` or,

mv = `"h"/lambda`

∴ v `"h"/("m"lambda)=(15"hR")/("m"16)`