Question

An object of mass 0.5 kg is executing a simple Harmonic motion. Its amplitude is 5 cm and the time period (T) is 0.2 s. What will be the potential energy of the object at an instant t = `T/4` s starting from the mean position? Assume that the initial phase of the oscillation is zero.

विकल्प

• 0.62 J

• 6.2 × 10^-3 J

• 1.2 × 10³ J

• 6.2 × 10³ J

Answer 1

0.62 J

Explanation:

P.E. = `1/2momega^2x^2 = 1/2m((2pi)/T)^2 xx A^2sin^2((2pi)/T)t`

Putting the value of m, A, and T, we get P.E. = 0.62 J