Advertisements
Advertisements
प्रश्न
An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?
उत्तर
Mass of the object = m
The initial velocity of the object = v,
The final velocity of the object = 0
Work done on the object = Change in kinetic energy of the object = Final kinetic energy − Initial kinetic energy
= `1/2 M xx (0) - 1/2 m . v^2`
= `(0) - 1/2 m . v^2`
= `-1/2 m . v^2`
The negative sign shows that the work done is opposite to the object's direction of motion.
APPEARS IN
संबंधित प्रश्न
A freely falling object eventually stops on reaching the ground. What happens to its kinetic energy?
Kinetic energy = 1/2 × mass × ............
When a boy doubles his speed, his kinetic energy becomes
A cannon ball of mass 500 g is fired with a speed of 15 m s-1. Find:
- its kinetic energy.
- its momentum.
How fast should a man of 50 kg run so that his kinetic energy be 625 J?
A ball of mass 200 g falls from a height of 5 metres. What is its kinetic energy when it just reaches the ground? (g = 9.8 m/s2)
A horse and a dog are running with the same speed. If the weight of the horse is ten times that of the dog, What is the ration of their kinetic energies?
Find out the form of energy possessed by the following thing.
A rolling ball
An apple falling from a tree is an example for kinetic energy.
A car of mass 120 kg is moving at a speed 18 km/h and it accelerates to attain a speed of 54 km/h in 5 seconds. Calculate:
- the work done by the engine.
- the power of the engine.