Question

An observer ${\displaystyle \sqrt{3}}$ m tall is 3 m away from the pole ${\displaystyle 2\sqrt{3}}$ high. What is the angle of elevation of the top?

विकल्प

• 60°

• 30°

• 45°

• 90°

Answer 1

30°

Explanation:

Height of the pole that is above man’s height ${\displaystyle =2\sqrt{3}-\sqrt{3}=\sqrt{3} \text{m}}$

Hence, AB = ${\displaystyle \sqrt{3}}$ m

BC = 3 m

Hence, tan C ${\displaystyle =\frac{\text{AB}}{\text{BC}}=\frac{\sqrt{3}}{3}=\frac{1}{\sqrt{3}}}$

${\displaystyle \Rightarrow \text{C, angle of elevation}={30}^{\circ }}$