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प्रश्न
Answer the following:
Find the trigonometric functions of :
−330°
उत्तर
Angle of measure (– 330°) :
Let m∠XOA = −330°
Its terminal arm (ray OA) intersects the standard unit circle at P(x, y).
Draw seg PM perpendicular to the X-axis.
∴ ΔOMP is a 30° – 60° – 90° triangle.
OP = 1
OM = `sqrt(3)/2"OP"`
= `sqrt(3)/2(1)`
= `sqrt(3)/2`
PM = `1/2"OP"`
= `1/2(1)`
= `1/2`
Since point P lies in the 1st quadrant,
x > 0, y > 0
∴ x = OM = `sqrt(3)/2 and y = "PM" = 1/2`
∴ P ≡ `(sqrt(3)/2, 1/2)`
sin (−330°) = y = `1/2`
cos (−330°) = x = `sqrt(3)/2`
tan (−330°) = `y/x = (1/2)/(sqrt(3)/2) = 1/sqrt(3)`
cosec (−330°) = `1/y = 1/((1/2))` = 2
sec (−330°) = `1/x = 1/((sqrt(3)/2)) = 2/sqrt(3)`
cot (−330°) = `x/y = (sqrt(3)/2)/((1/2)) = sqrt(3)`
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