Advertisements
Advertisements
प्रश्न
Answer the following in brief :
Acetic acid is 5% ionised in its decimolar solution. Calculate the dissociation constant of acid.
उत्तर
Given: Percent dissociation = 5%, Concentration (c) = 1 decimolar
To find: Dissociation constant of acid (Ka)
Formulae:
i. Percent dissociation = α × 100
ii. Ka = α2 c
Calculation:
Using formula (i),
α = `"Percent dissociation"/100 = 5/100 = 0.05`
c = 1 decimolar = 0.1 M
Using formula (ii),
Ka = (0.05)2 × (0.1)
= 2.5 × 10-4
The dissociation constant of acid is 2.5 × 10-4.
APPEARS IN
संबंधित प्रश्न
Answer the following in one sentence :
The dissociation constant of acetic acid is 1.8 × 10-5. Calculate percent dissociation of acetic acid in 0.01 M solution.
Derive Ostwald's dilution law for the CH3COOH.
What is the percentage dissociation of 0.1 M solution of acetic acid? \[\ce{[Ka(CH3COOH) = 10^{-5}]}\]
Write expression for dissociation constant for weak base BOH. How is it related to its degree of dissociation?
The dissociation constant (Kb) for NH4OH is 1.8 × 10−5. The degree of dissociation in 0.01 M solution is ______.
A weak monobasic acid of 0.04% dissociated in 0.025 M solution. Calculate the pH of the solution.
Derive Ostwald's dilution law for CH3COOH.
Derive Ostwald's dilution law for the \[\ce{CH3COOH}\].
Derive Ostwald's dilution law for the CH3COOH.
Derive Ostwald's dilution law for the \[\ce{CH3COOH}\].
Derive Ostwald's dilution law for the \[\ce{CH3COOH}\].
