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Answer the following in brief. Obtain the relationship between the rate constant and half-life of a first-order reaction. - Chemistry

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प्रश्न

Answer the following in brief.

Obtain the relationship between the rate constant and half-life of a first-order reaction.

योग

उत्तर

i. The integrated rate law for the first-order reaction is k = `2.303/"t" log_10  ["A"]_0/["A"]_"t"`

Where [A]0 is the initial concentration of the reactant at t = 0. The concentration falls to [A]t at time t after the start of the reaction. The concentration of the reactant falls to `["A"]_0/2` at time t1/2.

ii. The time required for [A]0 to become `["A"]_0/2` is denoted as `"t"_(1/2)` or `["A"]_"t" = ["A"]_0/2` at t = t1/2 

Putting this condition in the integrated rate law we write

k = `2.303/"t"_(1/2) "log"_10 ["A"]_0/(["A"]_0/2)`

= `2.303/"t"_(1/2) "log"_10 2`

Substituting the value of `log_10 2`,

k = `2.303/"t"_(1/2) xx 0.3010`

∴ k = `0.693/"t"_(1/2)`

∴ `"t"_(1/2) = 0.693/"k"`

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अध्याय 6: Chemical Kinetics - Exercises [पृष्ठ १३६]

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बालभारती Chemistry [English] 12 Standard HSC
अध्याय 6 Chemical Kinetics
Exercises | Q 3. iv. | पृष्ठ १३६

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