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Answer the following question: Evaluate determinant along second column |1-1232-201-2| - Mathematics and Statistics

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प्रश्न

Answer the following question:

Evaluate determinant along second column

`|(1, -1, 2),(3, 2, -2),(0, 1, -2)|`

योग

उत्तर

Let D = `|(1, -1, 2),(3, 2, -2),(0, 1, -2)|`

The expansion of the determinant D along second column is

D = – 1 (cofactor of – 1) + 2 (cofactor of 2) + 1 (cofactor of 1)

= `-1 xx (-1)^(1 + 2) |(3, -2),(0, -2)| + 2 xx (-1)^(2 + 2)|(1, 2),(0, -2)| + 1 xx (-1)^(2 + 3)|(1, 2),(3, -2)|`

= –1( –1) ( – 6 + 0) + 2 (1)( – 2 – 0) +1 ( –1)( –2 –  6)

= 1 ( – 6) + 2( – 2) – 1( – 8)

= –6 – 4 + 8

= – 2.

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Minors and Cofactors of Elements of Determinants
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Determinants and Matrices - Miscellaneous Exercise 4(A) [पृष्ठ ७६]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 4 Determinants and Matrices
Miscellaneous Exercise 4(A) | Q II. (2) | पृष्ठ ७६
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