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Answer the following question, which help you understand the difference between Thomson’s model and Rutherford’s model better. Is the average angle of deflection of α­-particles by a - Physics

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प्रश्न

Answer the following question, which help you understand the difference between Thomson’s model and Rutherford’s model better.

Is the average angle of deflection of α­-particles by a thin gold foil predicted by Thomson’s model much less, about the same, or much greater than that predicted by Rutherford’s model?

टिप्पणी लिखिए

उत्तर

About the same

The average angle of deflection of α­-particles by a thin gold foil predicted by Thomson’s model is about the same size as predicted by Rutherford’s model. This is because the average angle was taken in both models.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Atoms - Exercise [पृष्ठ ४३६]

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एनसीईआरटी Physics [English] Class 12
अध्याय 12 Atoms
Exercise | Q 12.11 (a) | पृष्ठ ४३६
एनसीईआरटी Physics [English] Class 12
अध्याय 12 Atoms
Exercise | Q 11.1 | पृष्ठ ४३६

संबंधित प्रश्न

In the ground state of ____________ electrons are in stable equilibrium, while in ____________ electrons always experience a net force. (Thomson’s model/Rutherford’s model)


Answer the following question, which help you understand the difference between Thomson’s model and Rutherford’s model better.

Keeping other factors fixed, it is found experimentally that for small thickness t, the number of α-particles scattered at moderate angles is proportional to t. What clue does this linear dependence on t provide?


Answer the following question, which help you understand the difference between Thomson’s model and Rutherford’s model better.

In which model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of α-particles by a thin foil?


In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 80, when a α-particle of 8Mev energy impinges on it before it comes momentarily to rest and reverses its direction.

How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?


In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 75, when a α-particle of 5 MeV energy impinges on it before it comes momentarily to rest and reverses its direction.

How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?


Answer the following question.
Explain briefly how Rutherford scattering of α-particle by a target nucleus can provide information on the size of the nucleus.


The model that best explains the results of Geiger-Marsden experiment is ______.


The first line of Balmer series (Hα) in the spectrum of hydrogen is obtained when an electron of hydrogen atom goes from ______.


For 7.7 Mev alpha particles scattering from aluminium (Z = 13), the distance of closest approach in a bead on collision is ______.

Useful data

`1/(4 pi ∈_0) = 8.99 xx 10^9` newton m2C-2; c = 1.60 × 10-19 C; leV = 1.60 × 10-19j.


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What is the nuclear radius of 125Fe, if that of 27Al is 3.6 fermi?


The energy of hydrogen atom in an orbit is −1.51 eV. What are the kinetic and potential energies of the electron in this orbit?


The electron in a hydrogen atom is typically found at a distance of about 5.3 × 10−11 m from the nucleus which has a diameter of about 1.0 × 10−15 m. Assuming the hydrogen atom to be a sphere of radius 5.3 × 10−11 m, what fraction of its volume is occupied by the nucleus?


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The shortest wavelength of the Brackett series of a hydrogen like atom of atomic number Z is same as the shortest wavelength of the Balmer series of hydrogen atom, then the value of Z is ______.


Choose the correct option from the following options given below:


An alpha nucleus of energy `1/2`mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to ______.

  1. v2
  2. `1/"m"`
  3. `1/"v"^2`
  4. `1/"Ze"`

Determine the distance of the closest approach when an alpha particle of kinetic energy 3.95 MeV approaches a nucleus of Z = 79, stops and reverses its directions.


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