Advertisements
Advertisements
प्रश्न
Atomic number of \[\ce{Mn, Fe, Co}\] and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?
(i) \[\ce{[MnCl6]^{3-}}\]
(ii) \[\ce{[FeF6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
(iv) \[\ce{[Ni(NH3)6]^{2+}}\]
उत्तर
(i) \[\ce{[MnCl6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
Explanation:
\[\ce{[MnCl6]^{3-} : MN^{3+} (3d^4)}\]
| `↑` | `↑` | `↑` | `↑` |
\[\ce{[CoF6]^{3-} : Co^{3+} (3d^6)}\]
| `↑↓` | `↑` | `↑` | `↑` | `↑` |
APPEARS IN
संबंधित प्रश्न
Draw the structures of the following :
(1) XeF6
(2) IF7
Complete and balance the following reactions:
(1) P4 + H2SO4 → ____ + _____ + _____ + _____
(2) Ag + HNO3(dilute) → _____ + ______ + _____ + _____
An aqueous pink solution of cobalt (II) chloride changes to deep blue on addition of excess of HCl. This is because:
(i) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl6]}^{4-}\]
(ii) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl4]}^{2-}\]
(iii) tetrahedral complexes have smaller crystal field splitting than octahedral complexes.
(iv) tetrahedral complexes have larger crystal field splitting than octahedral complex.
On the basis of crystal field theory explain why Co(III) forms paramagnetic octahedral complex with weak field ligands whereas it forms diamagnetic octahedral complex with strong field ligands.
Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?
[Ni(H2O)6]2+ (aq) is green in colour whereas [Ni(H2O)4 (en)]2+ (aq)is blue in colour, give reason in support of your answer.
Crystal field stabilising energy for high spind4 octahedral complex is:-
What is the difference between a weak field ligand and a strong field ligand?
What is crystal field splitting energy?
On the basis of Crystal Field theory, write the electronic configuration for the d5 ion with a strong field ligand for which Δ0 > P.
