Question

अवयव पाडा.

`16a^3 - 128/b^3`

Answer 1

आपणांस माहीत आहे की,

a³ − b³ = (a − b)(a² + ab + b²)

`16a^3 - 128/b^3`

= `16[a^3 - 8/b^3]`

= `16[(a)^3 - (2/b)^3]`

= `16[(a - 2/b) {(a)^2 + (a) xx (2/b) + (2/b)^2}]`

= `16(a - 2/b) (a^2 + (2a)/b + 4/b^2)`