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प्रश्न
`abs ((("b" + "c"^2), "a"^2, "bc"),(("c" + "a"^2), "b"^2, "ca"),(("a" + "b"^2), "c"^2, "ab")) =` ____________.
विकल्प
(a - b)(b - c)(c - a)(a2 + b2 + c2)
-(a - b)(b - c)(c - a)
(a - b)(b - c)(c - a)(a + b + c)(a2 + b2 + c2)
0
MCQ
रिक्त स्थान भरें
उत्तर
`abs ((("b" + "c"^2), "a"^2, "bc"),(("c" + "a"^2), "b"^2, "ca"),(("a" + "b"^2), "c"^2, "ab")) =` (a - b)(b - c)(c - a)(a + b + c)(a2 + b2 + c2).
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