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Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table: Number of defective bulbs 0 1 2 3 4 5 6 - Mathematics

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प्रश्न

Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table:

Number of defective bulbs 0 1 2 3 4 5 6 more than 6
Frequency 400 180 48 41 18 8 3 2

One carton was selected at random. What is the probability that it has

  1. no defective bulb?
  2. defective bulbs from 2 to 6?
  3. defective bulbs less than 4?
योग

उत्तर

Total number of cartons, n(S) = 700

i. Number of cartons which has no defective bulb,

 n(E1) = 400

∴ Probability that no defective bulb = `(n(E_1))/(n(S))`

= `400/700`

= `4/7`

Hence, the probability that no defective bulb is `4/7`.

ii. Number of cartons which has defective bulbs from 2 to 6, 

n(E2) =  48 + 41 + 18 + 8 + 3 = 118

∴ Probability that the defective bulbs from 2 to 6 = `(n(E_2))/(n(S))`

= `118/700`

= `59/350`

Hence, the probability that the defective bulbs from 2 to 6 is `59/350.`

iii. Number of cartons which has defective bulbs less than 4,

n(E3) =  400 + 180 + 48 + 41 = 669

∴ The probability that the defective bulbs less than 4 = `(n(E_3))/(n(S)) = 669/700`

Hence, the probability that the defective bulbs less than 4 is `669/700.`

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अध्याय 14: Statistics & Probability - Exercise 14.3 [पृष्ठ १४४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 14 Statistics & Probability
Exercise 14.3 | Q 18. | पृष्ठ १४४

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