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प्रश्न
Calculate the amount of lime {80 %purity) and soda {90% purity) required for softening of 50,000 of hard water whose chemical analysis results are given below. Ca(HCO3 ) = 40.5 mg/L, Mg( HCO3)2 = 73.0 mg/L, MgSO4 = 60.0 mg/L, CaSO4 = 34.0 mg/L, CaCl2 = 27.5 mg/L and NaCI = 20.0 mg/L.
उत्तर
| lmpurities(mg/lit) | Multiplication factor | CaC03 equivalent (mg/lit) | Requirement |
| Ca(HC03)2 =40.5 |
`100/162` | `40.5 xx 100/162 = 25` | L |
| Mg(HC03)2 =73.0 |
`100/146` | `73 xx 100/146 = 50` | 2L |
| CaCl2 = 27.5 | `100/111` | `27.5 xx 100/111 = 24.8` | S |
| CaS04 = 34 | `100/136` | `34 xx 100/136 = 25` | S |
| MgS04 = 60 | `100/120` | `60/100/120 = 50` | L+S |
NaCl does not react with lime and soda.
LIME = `74/100[CaCO_3 " equivalent of " Ca(HCO_3)_2 +2 xx Mg(HCO_3)_2+MgSO_4]xx ("Volume of water") /1000 xx 100/(%"purity")`
`= 74/100 xx [25 + 2 50 + 50] xx 50000/1000 xx 100 /80`
= 8093.75 gms.
`"SODA "= 106/100 [25+50+24.8] xx 100000/1000 xx 100/85.`
= 5877.1gms.
The lime requirement is 6541.6 gms and soda requirement is 8203. 15 gms.
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संबंधित प्रश्न
Calculate the quantity of the pure lime and soda required for softening of 1,00,000 litres of water containing the following impurities in ppm. The purity of lime is 70% and soda is BS% Ca(HCO3) = 30.2 , Mg(HCO3) = 20.8 ,CaCI2 = 28.1 ,MgCl2 = 8.78, CaSO4 = 35, MgSO4 = 6.7 .
Calculate the amount of lime (85% pure) and soda (95% pure) required to soften one million litre of water which contains CaCO3 = 12. 5ppml MgCO3 = 8.4ppml
CaCl2 = 22.2ppml , MgCl2 = 9.5ppml C02 = 33ppml HCI = Z3ppml organic matter= 16.Bppm
Write a note on Deccay of Concrete.
A sample of water contains following impurities :
Mg(HCO3)2 =73 mg/lit , MgSO4 = 120 mg/lit , CaCl2 = 222 mg/lit and Ca(NO3)2 = 164 mg/lit . The purity of lime is 74% and soda is 90% . Calculate the quantity of lime and soda needed for softening of 50,000 litres of water .
