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प्रश्न
Calculate the kinetic energy of a body of mass 0.1 kg. and momentum 40kg m/s.
उत्तर
K.E. = `1/2`mv2 and momentum P = mv
Eliminating v, K.E. =`1/2"m"xx("P"/"m")="P"^2/(2"m")`
Given : P = 40 kg m/s, m = 0.1 Kg.
K.E. = `(40)^2/(2xx0.1)` = 8000 J = 8 × 103 J.
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