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Calculate the pH of the following solution: 0.3 g of NaOH dissolved in water to give 200 mL of solution. - Chemistry

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प्रश्न

Calculate the pH of the following solution:  

0.3 g of NaOH dissolved in water to give 200 mL of solution.

संख्यात्मक

उत्तर

For 0.3 g of NaOH dissolved in water to give 200 mL of solution:

\[\ce{NaOH -> Na^+_{(aq)} + OH^-_{(aq)}}\]

`["NaOH"] = 0.3 xx 1000/200 = 1.5 "M"`

`["OH"_("aq")^-] = 1.5 "M"`

Then `["H"^+] = 10^(-14)/1.5`

`= 6.66 xx 10^(-13)`

`"pH" = - log(6.66  xx 10^(-13))`

=  12.18

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अध्याय 7: Equilibrium - EXERCISES [पृष्ठ २३७]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
अध्याय 7 Equilibrium
EXERCISES | Q 7.49 - c) | पृष्ठ २३७

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