Advertisements
Advertisements
प्रश्न
Calculate the temperature at which the rms velocity of a gas triples its value at S.T.P. (standard temperature T1 = 273 K)
उत्तर
At STP temperature T1 = 273 K
RMS velocity of a gas, (vrms)1 = v
New RMS velocity of a gas, at temperature (T2)
New temperature T2 = ?
vrms = `sqrt((3"RT")/"M")`
`("v"_"rms")_1/("v"_"rms")_2 = sqrt("T"_1/"T"_2)`
T2 = `[("v"_"rms")_2/("v"_"rms")_1]^2 xx "T"_1`
= `((3"v")/"v")^2 xx 273`
= 9 × 273
T2 = 2457 K
APPEARS IN
संबंधित प्रश्न
A fresh air is composed of nitrogen N2 (78%) and oxygen O2 (21%). Find the rms speed of N2 and O2 at 20°C.
If the rms speed of methane gas in the Jupiter’s atmosphere is 471.8 ms−1, shows that the surface temperature of Jupiter is sub-zero.
The number of molecules in 100 cc of gas at N.T.P. is ______ if the mass of each molecule is 4.556 x 10-25 kg and R.M.S. speed is 250 m/s.
The molecular weights of oxygen and hydrogen are 32 and 2 respectively. The root mean square velocities of oxygen and hydrogen at N.T.P. are in the ratio ______
The root mean square velocity of molecules of a gas is 200 m/s. What will be the root mean square velocity of the molecules, if the molecular weight is doubled and the absolute temperature is halved?
To what temperature should hydrogen at 227° C be cooled at constant pressure so that root mean square velocity of its molecule becomes half of its previous value?
The rms speed of oxygen molecule in a gas is u, If the temperature is doubled and the molecules dissociates into two atoms, the rms speed will be ______.
The temperature at which the molecules of nitrogen will have the same r.m.s. velocity as the molecules of oxygen at 327° C is ____________.
What will be the effect on the root mean square velocity of oxygen molecules if the temperature is doubled and the oxygen molecule dissociates into atomic oxygen?
Compare the rms speed of hydrogen molecules at 227°C with the rms speed of oxygen molecules at 127°C. Given that molecular masses of hydrogen and oxygen are 2 and 32 respectively.
