Question

Production of iron in a blast furnace follows the following equation:

\[\ce{Fe3O4 (s) + 4CO (g) -> 3Fe (l) + 4CO2 (g)}\]

When 4.640 kg of Fe₃O₄ and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is:

[Given: Molar Atomic mass (g mol⁻¹): Fe = 56

Molar Atomic mass (g mol⁻¹): O = 16

Molar Atomic mass (g mol⁻¹): C = 12]

विकल्प

• 1400

• 2200

• 3360

• 4200

Answer 1

3360

Explanation:

Moles of Fe₃O₄ = `4.640 xx 10^3/232`

Moles of CO = `2.52 xx 10^3/28` = 90 mol

\[\ce{Fe3O4 (s) + 4CO (g) -> 3Fe (l) + 4CO2 (g)}\]

Since 1 mole of Fe₃O₄ produces 3 moles of Fe. So, 20 moles of Fe₃O₄ produces 20 × 3 moles of Fe. Moles of Fe produced = 20 × 3 = 60 moles.

So, the weight of Fe = No. of moles produced × molar mass of Fe.

Weight of Fe = 60 × 56 = 3360 g.