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प्रश्न
Chlorophyll present in green leaves of plants absorbs light at 4.620 × 1014 Hz. Calculate the wavelength of radiation in nanometer. Which part of the electromagnetic spectrum does it belong to?
उत्तर
We know that
`lambda = c/u`
Given, `u` = 4.620 × 1014 Hz
Thus, `lambda = c/u` = (3.0 × 108 m/s)/(4.620 × 1014 Hz) = 649.4 nm
This frequency falls under visible range.
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