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प्रश्न
\[\begin{array}{cc}
\ce{CH3-CH-CH=CH2 + HBr -> A}\\
|\phantom{.....................}\\
\ce{CH3}\phantom{..................}
\end{array}\]
'A' is:
विकल्प
\[\begin{array}{cc}
\ce{Br}\phantom{.....}\\
|\phantom{......}\\
\ce{CH3-C-CH2-CH3}\\
|\phantom{......}\\
\ce{CH3}\phantom{....}
\end{array}\]\[\begin{array}{cc}
\ce{CH3-CH-CH-CH3}\\
\phantom{}|\phantom{.....}|\phantom{..}\\
\phantom{.}\ce{Br}\phantom{...}\ce{CH3}\phantom{}
\end{array}\]\[\begin{array}{cc}
\ce{CH3-CH-CH2-CH2Br}\\
|\phantom{..........}\\
\ce{CH3}\phantom{........}
\end{array}\]\[\begin{array}{cc}
\ce{BrCH2-CH-CH2-CH3}\\
|\phantom{......}\\
\ce{CH3}\phantom{....}
\end{array}\]
उत्तर
\[\begin{array}{cc}
\ce{Br}\phantom{.....}\\
|\phantom{......}\\
\ce{CH3-C-CH2-CH3}\\
|\phantom{......}\\
\ce{CH3}\phantom{....}
\end{array}\]