Advertisements
Advertisements
प्रश्न
\[\ce{CH3CH2CH = CH2 ->[B2H6][H2O, H2O2, OH^-] X}\]
What is X?
विकल्प
\[\ce{CH3CH2CH2CH3}\]
\[\ce{CH3CH2CH2CH2OH}\]
\[\begin{array}{cc}
\ce{CH3CH2CHCH3}\\
\phantom{...}|\\
\phantom{.....}\ce{OH}
\end{array}\]\[\ce{CH3CH2CH2CHO}\]
MCQ
उत्तर
\[\ce{CH3CH2CH2CH2OH}\]
Explanation:
According to Anti-rule, Markovnikov's hydroboration-oxidation process involves the addition of −H and −OH to unsymmetrical alkenes. As a result, butan-1-ol is the end product.
\[\ce{\underset{But-1-ene}{6CH3CH2CH = CH2} + \underset{Diborane}{B2H6} -> 2(CH3CH2CH2CH2)3B (CH3CH2CH2CH2)3B + 3H2O2 ->[OH^-][-B(OH)3] \underset{Butan-1-ol}{3CH3CH2CH2CH2OH}}\]
shaalaa.com
Alkenes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?