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प्रश्न
Complete the following fission reaction:
\[\ce{_92U^235 _0n^1 -> _aSb^133 + _41Co^b + 4_0n_1 + energy}\]
Write down the values of a and b.
उत्तर
\[\ce{_92U^235 _0n^1 -> _aSb^133 + _41Co^b + 4_0n_1}\]
Hence, 235 + 1 = 133 + b + 4
or 236 = b + 137
∴ b = 236 - 137 = 99
Similarly 92 = a - 41
∴ a = 92 - 41 = 51
Hence, \[\ce{_92U^235 _0n^1 -> _aSb^133 + _41Co^b + 4_0n_1}\]
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