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प्रश्न
complete the following reaction:
\[\begin{array}{cc}
\phantom{...}\ce{CH3} \\
| \\
\phantom{.................}\ce{CH3-CH-COOH ->[(i) Br2/Red P4][(ii)H2O]}
\end{array}\]
उत्तर
Carboxylic acid having a-hydrogen are halogenated at a-position on treatment with 2 Br in presence of red phosphorous to give a -halocarboxylic acids. This is the HeII-Volhard-Zelinsky reaction.
\[\begin{array}{cc}
\phantom{.................}\ce{CH3}
\phantom{...........................}\ce{CH3}\\
\phantom{...............}|
\phantom{..............................}| \\
\phantom{.................}\ce{CH3-CH-COOH ->[(i) Br2/Red P4][(ii)H2O]CH3-C-COOH}\\
\phantom{.............................................} | \\
\phantom{..............................................} \ce{Br}
\end{array}\]
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\[\begin{array}{cc}
\ce{D}\phantom{........................}\\
|\phantom{.........................}\\
\ce{2D - C = O + OH^- ->[Cannizzaro] X and Y}
\end{array}\]
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