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प्रश्न
Complete the table and find the solution of the equation `"z"/3 = 4` using the table.
|
z |
8 |
9 |
10 |
11 |
12 |
13 |
14 |
15 |
16 |
______ |
|
`"z"/3` |
`2 2/3` |
3 |
`3 1/3` |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
उत्तर
For `"z"/3`, the table can be constructed as follows.
-
z
`"z"/3`
8
`8/3 = 2 2/3`
9
`9/3 = 3`
10
`10/3 = 3 1/3`
11
`11/3 = 3 2/3`
12
`12/3 = 4`
13
`13/3 = 4 1/3`
14
`14/3 = 4 2/3`
15
`15/3 = 5`
16
`16/3 = 5 1/3`
By inspection, we can find that z = 12 is the solution of the above equation as for z = 12, `"z"/3` = 4
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Complete the entries in the third column of the table.
|
S.No. |
Equation |
Value of variable |
Equation satisfied Yes/No |
|
(a) |
10y = 80 |
y = 10 |
______ |
|
(b) |
10y = 80 |
y = 8 |
______ |
|
(c) |
10y = 80 |
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______ |
|
(d) |
4l = 20 |
l = 20 |
______ |
|
(e) |
4l = 20 |
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______ |
|
(f) |
4l = 20 |
l = 5 |
______ |
|
(g) |
b + 5 = 9 |
b = 5 |
______ |
|
(h) |
b + 5 = 9 |
b = 9 |
______ |
|
(i) |
b + 5 = 9 |
b = 4 |
______ |
|
(j) |
h − 8 = 5 |
h = 13 |
______ |
|
(k) |
h − 8 = 5 |
h = 8 |
______ |
|
(l) |
h − 8 = 5 |
h = 0 |
______ |
|
(m) |
p + 3 = 1 |
p = 3 |
______ |
|
(n) |
p + 3 = 1 |
p = 1 |
______ |
|
(o) |
p + 3 = 1 |
p = 0 |
______ |
|
(p) |
p + 3 = 1 |
p = − 1 |
______ |
|
(q) |
p + 3 = 1 |
p = − 2 |
______ |
