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Consider a quantity of a radioactive substance. The fraction of this quantity that remains after t half-lives can be found by using the expression 3–t. - Mathematics

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प्रश्न

Consider a quantity of a radioactive substance. The fraction of this quantity that remains after t half-lives can be found by using the expression 3–t. After how many half-lives will the fraction be `1/243` of the original?

योग

उत्तर

Given, t half-lives = 3–t

So, `1/243 = 3^-t`

⇒ `1/3^5 = 1/3^t`  ...`[because 3 xx 3 xx 3 xx 3 xx 3 = 3^5  "and"  a^-m = 1/a^m]` 

On comparing both sides, we get t = 5 half-lives.

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अध्याय 8: Exponents and Powers - Exercise [पृष्ठ २६४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
अध्याय 8 Exponents and Powers
Exercise | Q 140. (b) | पृष्ठ २६४

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