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प्रश्न
Consider the following reaction.
I. \[\ce{Na2B4O7 ->[760° C] {...A...} + B2O3}\]
II. \[\ce{Si + KOH + H2O ->{...B...} + H2\uparrow}\]
III. \[\ce{P2O5 + HNO3 -> HPO3 + {...C...}}\]
IV. \[\ce{NH3 + Cl2(excess) -> {...D...} + HCl}\]
Identify the missing products of the given reactions.
विकल्प
\[\ce{A - Na2O; B - KSiO3; C - N2O4; D - NCl3}\]
\[\ce{A - NaBO2; B - K2SiO3; C - N2O5; D - NCl3}\]
\[\ce{A - NaBO2; B - K2SiO3; C - N2O4; D - \overset{⊕}{N}Cl4}\]
\[\ce{A - Na2O; B - K2SiO3; C - N2O5; D - NCl3}\]
उत्तर
\[\ce{A - NaBO2; B - K2SiO3; C - N2O5; D - NCl3}\]
Explanation:
\[\ce{Na2B4O7 ->[760° C] \underset{(A)}{2NaBO2} + B2O3}\]
\[\ce{Si + 2KOH + H2O ->\underset{(B)}{K2SiO3} + 2H2\uparrow}\]
\[\ce{P2O5 + 2HNO3 -> 2HPO3 + \underset{(C)}{N2O5}}\]
\[\ce{NH3 + 3Cl2 (excess) ->\underset{(D)}{NCl3} + 3HCl}\]
