हिंदी

Consider the following reactions. CA6HA5NA2+ClA−→HBFA4A→NaNOA2/CuB→Sn/HClC Identify the compound formed C in the above reaction. -

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प्रश्न

Consider the following reactions.

\[\ce{C6H5N^+_2Cl- ->[HBF4] A ->[NaNO2/Cu] B ->[Sn/HCl] C}\]

Identify the compound formed C in the above reaction.

विकल्प

  • Nitrobenzene 

  • Aniline

  • Chloro benzene 

  • Phenol

MCQ

उत्तर

Aniline

Explanation

\[\ce{\underset{chloride}{\underset{Benzene diazonium }{C6H5N^+_2Cl-}} ->[HBF4] \underset{(A)}{C6H5N^+_2BF^-_4} ->[NaNO2/Cu][\Delta] \underset{Nitro benzene}{C6H5NO2} ->[Sn/HCl] \underset{Aniline}{\underset{(C)}{C6H5NH2}}}\]

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