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प्रश्न
Construct a parallelogram ABCD in which AB = 4.5cm, ∠A = 105° and the distance between AB and CD is 3.2cm.
उत्तर
Steps of construction:
1) Draw line AB = 4.5cm.
2) At B, draw BX perpendicular to AB.
3) From BX, cut BR = 3.2cm = distance between AB and CD.
4) Through R, draw a line perpendicular to BX to get QR parallel to AB.
5) With A as centre, draw a ray AP making an angle of 105 with AB and meeting QR at D.
6) With B as centre, draw an arc with radius = AD on QR and mark it as C.
7) Join BC.
8) ABCD is the required parallelogram.
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