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Construct a Rhombus Whose Perimeter is 16cm and Bd = 6.2cm. - Mathematics

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प्रश्न

Construct a rhombus whose perimeter is 16cm and BD = 6.2cm.

योग

उत्तर


The length of all the sides of rhombus is equal.
Hence, perimeter = side x 4
⇒ Side

= `"perimeter"/(4)`

= `(16)/(4)`
= 4cm
Steps of construction:
1) Draw BD = 6.2cm.
2) With B as centre and radius 4cm, draw two arcs one above BD and the other below BD.
3) With D as centre and radius 4cm draw two arcs one above BD and the other below BD intersecting the arcs of Steps 2 in A and C respectively.
4) Join AB, BC, CD and AD.
5) ABCD is the required rhombus.

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Construction of Rhombus
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 20: Constructions of Quadrilaterals - Exercise 20.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 20 Constructions of Quadrilaterals
Exercise 20.1 | Q 7
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