Advertisements
Advertisements
प्रश्न
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
उत्तर
Steps of Construction :
(i) Draw a line segment AB = 6 cm
(ii) At A, construct an angle equal to 45°
(iii) Cut off AC = 6 cm
(iv) Join BC.
∆ ABC is the required triangle.
On measuring, ∠B and ∠C, each is equal 1° to, 67`1/2°`
APPEARS IN
संबंधित प्रश्न
Construct a ∆ABC such that:
AB = 6 cm, BC = 4 cm and CA = 5.5 cm
Construct a ∆ABC such that:
BC = 4 cm, AC = 5 cm and AB = 3.5 cm
Construct a ∆ PQR such that:
PR = 5.8 cm, ∠P = 60° and ∠R = 45°. Measure ∠Q and verify it by calculations
Construct an isosceles Δ ABC such that:
Base BC = 4 cm and base angle = 30°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
BC = AB = 5.8 cm and ZB = 30°. Measure ∠A and ∠C.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
