Advertisements
Advertisements
प्रश्न
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
उत्तर
Steps of construction:
Step 1: Draw a line segment BC of 6cm.
Step 2: At B draw an angle le × BC of 90° .
Step 3: with center B and radius 10cm draw an arc which intersects XB at D.
Step 4: Join DC.
Step 5: Draw the perpendicular bisector of DC which intersects DB at A
Step 6: Join AC
∴ΔABC is the required triangle
APPEARS IN
संबंधित प्रश्न
Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.
Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.
Using ruler and compasses only, construct a ΔABC, given base BC = 7cm, ∠ABC = 60° and AB + AC = 12 cm.
Construct a triangle whose perimeter is 6.4 cm, and angles at the base are 60° and 45° .
Construct a right-angled triangle whose perimeter is equal to 10 cm and one acute angle equal to 60°.
Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.
A triangle ABC can be constructed in which BC = 6 cm, ∠C = 30° and AC – AB = 4 cm.
A triangle ABC can be constructed in which ∠B = 105°, ∠C = 90° and AB + BC + AC = 10 cm.
Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
