Advertisements
Advertisements
प्रश्न
Convert given fraction into a fraction with equal numerators:
`15/19, 25/28, 9/11 "and" 45/47`
उत्तर
In `15/19, 25/28, 9/11 "and" 45/47`,
L.C.M. of 15, 25, 9 and 45 = 225
`therefore 15/19 = (15 xx 15)/(19 xx 15) = 225/285`
`25/28 = (25 xx 9)/(28 xx 9) = 225/252`
`9/11 = (9 xx 25)/(11 xx 25) = 225/275`
and `45/47 = (45 xx 5)/(47 xx 5) = 225/235`
Hence the required fractions are `225/285, 225/252, 225/275 "and" 225/235`
APPEARS IN
संबंधित प्रश्न
Find the greater fraction:
`3/5 "and" 11/15`
Insert one fraction between:
`9/17 "and" 6/13`
Reduce to a single fraction:
`1 1/3 + 2 1/4`
Reduce to a single fraction:
`2/3 - 3/5 + 3 - 1/5`
Reduce to a single fraction:
`2/3 - 1/5 + 1/10`
Simplify: `3 div 2/5`
Simplify: `3 3/4 xx 1 1/5 xx 20/21`
Subtract: `2/9 "from" 4/5`
Simplify and reduce to a simple fraction:
`2/3 xx 1 1/4 div 3/7 "of" 2 5/8`
What number should be added to `8 2/3` to `12 5/6`.