हिंदी

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15 m, 10 m, and 7 m, respectively. From each can of paint, 100 m2 of area is painted. How many cans - Mathematics

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प्रश्न

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15 m, 10 m, and 7 m, respectively. From each can of paint, 100 m2 of area is painted. How many cans of paint will she need to paint the room?

योग

उत्तर

Given that,

Length (l) = 15 m,

breadth (b) = 10 m,

height (h) = 7 m

Area of the hall to be painted = Area of the wall + Area of the ceiling

= 2h (l + b) + lb

= [2(7) (15 + 10) + 15 ×10] m2

= [14(25) + 150] m2

= [350 + 150] m2

= 500 m2

It is given that 100 m2 area can be painted from each can.

Number of cans required to paint an area of 500 m2

= `500/100`

= 5 cans

Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.

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अध्याय 11: Mensuration - Exercise 11.3 [पृष्ठ १८६]

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एनसीईआरटी Mathematics [English] Class 8
अध्याय 11 Mensuration
Exercise 11.3 | Q 5 | पृष्ठ १८६
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